What's Your Number?

cqpkytty • 30 May 2012 at 11:45 AM

How to find your special number:
instructions (example)
1. Take the year you were born in. (1999)
2. Add the prime factors of the month and date of your birthday (June 6, so 1999+2+3+2+3=2009)
3. Multiply by the sum of the values of your initials (CQP, so 2009x(3+17+16)=7234)
4. Divide by 2 (72324/2=36162)
5. Add the digits together. (3+6+1+6+2=18)
6. Repeat step 5 until you have a single digit. (1+8=9)
7. Square this number. (9x9=81)
8. List the prime factors in order from least to greatest. (3, 3, 3, 3)
9. Take the first number in the list. (3)

The (parentheses) were for me. Do it for yourself and have fun! 😃

Pings:
@samattitude
@lola622f
@wererage
@sakura2596
@snowrosehell

snowrosehell • 30 May 2012 at 12:39 PM

Uggghhhh.... Maths! -__-
My head is spinning right now... >_<"

Oh well...
2) =2007
3) 2007(24+3+12)--&gt; 39= 78273
4) 39136.5
5) 27
6) 9 -By the way this looks... my guess we had same number.. xD-
7) 6
8) 5
9) 25= 27
10) 3 3 3
11) 3
12) It's...... 3! xD

sakura2596 • 30 May 2012 at 1:26 PM

@cqpkytty I got 3! 😸

april__ • 30 May 2012 at 8:00 PM

I'm pretty sure this is one of those things where it's always 3. XD

darcy_vasquez • 30 May 2012 at 8:03 PM

@april__

Yup... mine is 3 too!

cqpkytty • 30 May 2012 at 9:07 PM

@snowrosehell
Wait, you're 5 years old?
@sakura2596
@april__
@darcy_vasquez
It is?!?! O.O Wow, I had no idea!
And it isn't one of those things where the answer will always be 3, I made up the steps myself.

Here, let me try:

Let's say there was someone named Alfred Aderson, born on Jan 1, 2002. 😋
1. 2000
2. 2000+1+1=2002
3. 2002*(1+1)=4004
4. 4004/2=2002
5. 2+0+0+2=4
6. 4
7. 2+2=4.
8. 2+2=4. 2+2=4. 2+2=4...

Well, now we know for sure that it isn't ALWAYS 3. Sometimes you get stuck in an endless loop on #8. xP

I'll try again.
Betty Aderson. Same birth date. 😋
1. 2000
2. 2000+1+1=2002
3. 2002*(2+1)=6006
4. 6006/2=3003
5. 3+0+0+3=6
6. 6
7. 2+3=5

Hmm, and from there it's just the same...
OK, changing it. Check again now 😊

EDIT: OK, so now Alfred's number is 2, but Betty's is still 3. 😋 Good enough! 😸

snowrosehell • 2 June 2012 at 9:02 AM

@cqpkytty - Mwaa? .___. *looks at self* I am too intelligent for a 5 yrs. old.. xD 😋

karamel • 2 June 2012 at 9:36 AM

1. Take the year you were born in. (2000)
2. Add the prime factors of the month and date of your birthday (December 11, so 2000+12+11=2023)
3. Multiply by the sum of the values of your initials (CJ, so 2023x(3+10)=26299)
4. Divide by 2 (26299/2=13149.5)
5. Add the digits together. (1+3+1+4+9+5=14)
6. Repeat step 5 until you have a single digit. (1+4=5)
7. Square this number. (5x5=25)
8. List the prime factors in order from greatest to least. (5)
9. Take the first number in the list. (5)

Done, I think.

Number 5 *-* Wait, for @cfmtfm...
1. Take the year you were born in. (2000)
2. Add the prime factors of the month and date of your birthday (December 1, so 2000+12+1=2013)
3. Multiply by the sum of the values of your initials (SJ, so 2023x(19+10)=58667)
4. Divide by 2 (58667/2=29333.5)
5. Add the digits together. (2+9+3+3+3+5=25)
6. Repeat step 5 until you have a single digit. (2+5=7)
7. Square this number. (7x7=49)
8. List the prime factors in order from greatest to least. (7)
9. Take the first number in the list. (7)

7. Wow. She will be very happy with that. *coughcough* Alexander Ludwig *coughcough* xD

cqpkytty • 2 June 2012 at 10:13 AM

@snowrosehell
@karamel
I never said this was your AGE. -.-

karamel • 2 June 2012 at 12:09 PM

@cqpkytty I wasn't the one who said this was my age... you told snowrosehell that.

@snowrosehell Because you put 2007 for number 2, Cqpkytty thought that was your birth year, therefore you were 5 years old.

snowrosehell • 3 June 2012 at 3:25 AM

@karamel - Lol. I know.. I realized that one. She mistook number 2 as one. xD

@cqpkytty- Yes, I know you didn't. 😸~

cqpkytty • 3 June 2012 at 4:48 PM

@karamel
@snowrosehell
Actually, I told you guys that because @snowrosehell said she was too smart for a 5-year-old 😋

snowrosehell • 4 June 2012 at 4:05 AM

@cqpkytty - Well, you asked like 'you're 5 years old?' or something so, I just...... Ohhh... Sorry for the sarcasm. 😸~

sciteccf • 4 June 2012 at 8:00 AM

1. Take the year you were born in. (1999)
2. Add the prime factors of the month and date of your birthday (November 29, so 1999+12+30=2041)
3. Multiply by the sum of the values of your initials (CF, so 2041*(3+6)=18369)
4. Divide by 2 (9184.5)
5. Add the digits together. (9+1+8+4+5=27)
6. Repeat step 5 until you have a single digit. (2+7=9)
7. Square this number. (9*9=81)
9. List the prime factors in order from greatest to least. (3, 3, 3, 3)
10. Take the first number in the list. If it has multiple digits, repeat steps 5 and 6. (3)
11. This is your number. Congratulations! (3)

Also 3.

mrdonut • 4 June 2012 at 11:28 AM

@cqpkytty
too hard, i'll guess, my number is 4 XD

cqpkytty • 4 June 2012 at 8:49 PM

@sciteccf
Um, I changed it a few days ago, there's only 9 steps now 😋

@mrdonut
Haha 😋

sciteccf • 5 June 2012 at 10:45 AM

@cqpkytty Oh. It's still 3 though.

cqpkytty • 5 June 2012 at 6:23 PM

@sciteccf
Oh well, not all of them are, though 😋

morgana • 5 June 2012 at 6:44 PM

1. Take the year you were born in. (1997)
2. Add the prime factors of the month and date of your birthday (May 16, so 1997+16+4= 2017)
3. Multiply by the sum of the values of your initials (MC, so 2017*(3+13)=32,272)
4. Divide by 2 (32,272)= 16,136
5. Add the digits together. (1+6+1+3+6)=17
6. Repeat step 5 until you have a single digit. (1+7=8)
7. Square this number. (8*8=64)
9. List the prime factors in order from greatest to least. (2,2,2,2,2,2)
10. Take the first number in the list. (2)
11. This is your number. (2) 😊

cqpkytty • 5 June 2012 at 7:28 PM

@morgana
😊