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puppyloverlauren • 25 September 2012 at 8:05 PM
I need help, there is this one question that is hard for me. I am in Algebra and here is the problemb+c=10/a (10 over a) solve for aplease ping me how to the steps!
twilight_raptor • 25 September 2012 at 8:06 PM
b+c= 10/aa(b+c)= 10a= 10/(b+c)get how I obtained the answer? 😸a detailed one:b+c= 10/a(multiply a on both sides to cancel it out on the right)a(b+c)= (10/a) x a(a is canceled out and: ...)a(b+c)= 10(now isolate a by dividing both sides by (b+c) which would cancel (b+c) out on the left)(a(b+c))/(b+c) = 10/(b+c)((b+c) cancels out and..)a= 10/(b+c)
puppyloverlauren • 25 September 2012 at 8:08 PM
how do you get the third step?@twilight_raptor
twilight_raptor • 25 September 2012 at 8:11 PM
@puppyloverlauren edited my first post ^^
ladybugheart • 25 September 2012 at 8:11 PM
I'll try it out. o_ob+c=10/aSo, I believe you're supposed to multiply both sides by 1/10 (the reciprocal of 10) to cancel out the 10.1/10 (b+c) = aThen, use the distributive property. I'll change 1/10 to a decimal because it's easier for me..1b +.1c = aI believe that's the answer, but don't blame me if it's wrong. xD
meixiaotian • 25 September 2012 at 8:17 PM
b+c=10/aThen I multiplied both sides by 10.So 10(b+c)=aSo, as another different answer,10b+10c=aHave fun figuring out the real answer. XD
2-dgorillaz • 25 September 2012 at 8:24 PM
HOLY MOTHER OF GOD WHAT IS THIS!!!!!!????
twilight_raptor • 25 September 2012 at 8:41 PM
@ladybugheart when you cancel 10 out on one side by multiplying 1/10 on both sided you get:(b+c)/10= 1/a@meixiaotianmultiplying both sides by 10 wont work (:(b+c)=10/a10(b+c)= (10/a) x1010(b+c) = 100/a that goes the wrong way...
puppyloverlauren • 25 September 2012 at 10:24 PM
@twilight_raptor thank you! ahh this lesson is soo hard thank you for telling and explaing this to me!
twilight_raptor • 26 September 2012 at 11:44 AM
@puppyloverlauren no problem 😊 glad you understand 😸
puppyloverlauren • 26 September 2012 at 6:36 PM
@twilight_raptor 😊